By my reckoning, the energy in L1 is 720 nJ at the peak of the ramp, and the energy in L1+L2 just after the FET opens is 490 nJ. But this isn't it. Your graph looks wrong. How to simulate a tapped inductor in EasyEDA. The inductors or coils are passive components that have a certain number of turns of wire that introduce magnetic inductance to an electrical circuit to produce a magnetic flux or to mechanically react to magnetic flux variations.

A 1732 uH inductor at 30 mA contains 779 nJ. In this case, L1 is smaller than L2, so the input current pulse will be larger than the output. Somehow, the waveform I posted in a comment below doesn't show now. We use cookies to offer you a better experience. I can post the LTspice file tomorrow if anyone else wants to look. It tries to decrease coupling to have leakage inductance act as diff mode filter. About Us Especially when you are drawing so little current. Yes, the K coefficient is key. That's assuming discrete inductors. 1 Open switch , 2 single pole double throw switch , 3 push button switch ( open push switch ) , 4 closed push switch , 5 double pole double throw switch . Multi-year always-on LED replacements for gaseous tritium light sources. Place a coupling directive in the form of: K1 L1 L2 1 (with the 'Text type = spice' set in the right hand properties panel). I have about 10 pounds of cores of all sizes and materials in ferrite and powdered iron - I'm sure I could prototype something, but designing using off-the-shelf magnetics would be preferable. How to simulate a tapped inductor in EasyEDA. An electronic symbol is a pictogram used to represent various electrical and electronic devices or functions, such as wires, batteries, resistors, and transistors, in a schematic diagram of an electrical or electronic circuit.These symbols are largely standardized internationally today, but may vary from country to country, or engineering discipline, based on traditional conventions. You've created the inductor version of that. You treat them as two separate inductors to get 1.1mH, but that's inaccurate. :)  The core is lossy at high frequency, but that shouldn't be an issue. If it's tapped, there's going to be significant amounts of mutual inductance and that's basically an autotransformer. (Unless you get the phase wrong, then you get a non-inductive wirewound resistor.). Both sections together then have N(1 + sqrt(10)) turns. With the coupling, it's an autotransformer. This question is for testing whether you are a human visitor and to prevent automated spam submissions. 12.5V is probably a deal-breaker for a lot of LEDs. 2) Have you heard of the "capacitor paradox" (that isn't really a paradox)?